What is the percent ionization of a 0.20 M solution of C6H5COOH with Ka of 6.5 x 10-5 ?

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What is the percent ionization of a 0.20 M solution of C6H5COOH with Ka of 6.5 x 10-5 ? 
Benzoic acid dissociates as follows: 
C6H5COOH ==== C6H5COO
- + H+ 
Ka = [C6H5COO
-][ H+] / [C6H5COOH] 
Concentration of C6H5COOH = 0.20 M 
Ka = 6.5 x 10
-5 
If x amount of C6H5COOH dissociates then the concentrations of conjugate base and H
+   
will be equal to x amount.  
[C6H5COOH] = 0.

What is the percent ionization of a 0.20 M solution of C6H5COOH with Ka of 6.5 x 10-5 ?

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