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Name                                    
Group             

Results
1. Qualitative examination of equili
ia and Le Chatelier's Principle (20 pts)
(You may scan and incorporate a pdf of your group’s data sheet.)
    Well #
    Contents (drops)
    Observations
    
1
    
Fe(NO3)3 [3]
    
    
2
    
KSCN [3]
    
    
3
    
Fe(NO3)3 [1]/KSCN [1]
    
    
4
    
Fe(NO3)3 [2]/KSCN [2]
    
    
5
    
Fe(NO3)3 [3]/KSCN [3]
    
    
    For 6-13 all wells start with: Fe(NO3)3 [3]/KSCN [3]
    
    
6
    
Distilled water [2] (control)
    
    
7
    
Fe(NO3)3 [2]
    
    
8
    
KSCN [2]
    
    
9
    
KSCN [4]
    
    
10
    
KSCN [1, 1M]
    
    
11
    
Na2HPO4 [2]
    
    
12
    
H2SO4 [2]
    
    
13
    
KSCN [1, 1M]/H2SO4 [3]
    
    
    For 14-18 materials are: 0.0025M Fe(NO3)3
0.1M HNO3/1M KSCN
    
    
14
    
As above 1/4/4
    
    
15
    
As above 2/3/4
    
    
16
    
As above 3/2/4
    
    
17
    
As above 4/1/4
    
    
18
    
As above 5/0/4
    

1.
2. Beer's Law Plot for the Abso
ance of Fe(SCN XXXXXXXXXXpts)
(You may scan and incorporate a pdf of your group’s data sheet or include a pdf of your group’s Excel page.)
    Test Tube #
    
[Fe3+]initial=[Fe(SCN)2+]eq
    
A475
    
1
    
    
    
2
    
    
    
3
    
    
    
4
    
    
    
5
    
    
    
6
    
    
    
7
    
    
    Slope of line (A475 vs. [Fe(SCN)2+]) = ε =
    
1. Abso
ance measurements to determine the Equili
ium Constant (20 pts)
    Test Tube #
    
[Fe(SCN)2+]eq
    
A475
    
10
    
    
    
11
    
    
    
12
    
    
    
13
    
    
    
14
    
    
    
15
    
    
    
16
    
    
    
17
    
    
    
18
    
    
    
19
    
    

1. Calculation of the Equili
ium Constant Keq (called Kc in the text) (30 pts)

    Test Tube #
    
[Fe3+]initial
    
[SCN-]initial
    
[FeSCN2+ ]eq
    
[Fe3+ ]eq
    
[SCN- ]eq
    
keq
    
10
    
    
    
    
    
    
    
11
    
    
    
    
    
    
    
12
    
    
    
    
    
    
    
13
    
    
    
    
    
    
    
14
    
    
    
    
    
    
    
15
    
    
    
    
    
    
    
16
    
    
    
    
    
    
    
17
    
    
    
    
    
    
    
18
    
    
    
    
    
    
    
19
    
    
    
    
    
    
    Average value for Keq =
    
    
Questions (10 pts)
· Explain in the context of Le Chatelier's Principle why it is mathematically acceptable to assume that the initial concentration of the iron (III) ion, [Fe3+], is equal to the equili
ium concentration of the complex ion, [FeSCN2-], for the Beer’s Law determination (Part 2).
· If the class results for the were generally lower than the established value for Keq for this reaction, what might have caused the value to vary. This would seem to be a result of inaccuracies in the reported (labeled) concentrations of the reagents. What specific inaccuracies might have cause the generally lower values in the class results. Explain your answer. This is a mathematical question and requires a mathematical answer.
Results
1
Qualitative examination of equili
ia and Le Chatelier's Principle
Well | Contents (drops) | Observations
|| FeO 3] Mo color chanse, clear Ligued
2 KSCN [3]
No dor change, cleer isu d

Fe(NOW: [1VKSCN 1]
Solation Ained orange

Fe(NOu): [2/KSCN [2]

Fe(NOs)s [3YKSCN [3]
Ugh orange gobo
| Orange coludion

For 6-13 all wells start with:
Fe(NOy), [3/KSCN [3]

Distilled water [2] (control)
| chear—sobation 00 change gitubion EN ee
HiS04 [2]
7 | Fe(NOs) [2] no change, solubim dx dae orange
8 Kscn) no change
9 | Kson fg no change
10 |Ksont, IM) B lukon changed dom ormnge Av Sn
| NaHPOL [2] orange Ao des golden
2 oranse “ho cles Solution

KSCN [1, IMJH:SO4 [3]
orange to reddich-orange solubion

Tor 14-18 materials are:
0.0025M Fe(NO3),/0-1M HNO IM KSCN

As above 1/4/4
orange solukim
15 | Asabove 23/4 Ak cranae solakion
16 | Asabove 32/4 eMich orange soluion
17 | Asabove ana Jacle- vec. oranga_silotion
18 As above 5/0/4

ced solabm (deb)

2. Beer's Law Abso
ance Data (Abso
ance of Fe(SCN)™")
Bring these data to my desk before continuing to Part 3.
[Test Tube # | Ae
1 0.091 .
2 0-144 ~
[3 | omy |
4 0.248 } _
s 0-207 _
6 0-460 .
7 0-55

3. Abso
ance data to determine the Equili
ium Constant
Do not expect these measurements to be linear. There is no need for me to see them during the lab.
Test Tube # Asse
0 S¥ oma
| mn oan
2 0-394
XXXXXXXXXX -
14 0.26%
| 15 0-4dy
XXXXXXXXXX
XXXXXXXXXX
18 0386
Lr los |
Answered Same Day Apr 16, 2024

Solution

P answered on Apr 17 2024
8 Votes
Name                                    
Group             

Results
1. Qualitative examination of equili
ia and Le Chatelier's Principle (20 pts)
(You may scan and incorporate a pdf of your group’s data sheet.)
    Well #
    Contents (drops)
    Observations
    
1
    
Fe(NO3)3 [3]
    No color change, clear liquid
    
2
    
KSCN [3]
    No color change, clear liquid
    
3
    
Fe(NO3)3 [1]/KSCN [1]
    Solution turned orange
    
4
    
Fe(NO3)3 [2]/KSCN [2]
    Light orange solution
    
5
    
Fe(NO3)3 [3]/KSCN [3]
    Orange solution
    
    For 6-13 all wells start with: Fe(NO3)3 [3]/KSCN [3]
    
    
6
    
Distilled water [2] (control)
    No change in solution, stayed orange
    
7
    
Fe(NO3)3 [2]
    No change, solution stayed orange
    
8
    
KSCN [2]
    No change
    
9
    
KSCN [4]
    No change
    
10
    
KSCN [1, 1M]
    Solution changed from orange to reddish orange
ed
    
11
    
Na2HPO4 [2]
    Orange to clear solution
    
12
    
H2SO4 [2]
    Orange to clear solution
    
13
    
KSCN [1, 1M]/H2SO4 [3]
    Orange to reddish-orange solution
    
    For 14-18 materials are: 0.0025M Fe(NO3)3
0.1M HNO3/1M KSCN
    
    
14
    
As above 1/4/4
    Orange solution
    
15
    
As above 2/3/4
    Dark orange solution
    
16
    
As above 3/2/4
    Reddish-orange solution
    
17
    
As above 4/1/4
    Dark-red orange solution
    
18
    
As above 5/0/4
    Red solution (dark)

1.
2. Beer's Law Plot for the Abso
ance of Fe(SCN)2+ (20 pts)
(You may scan and incorporate a pdf of your group’s data sheet or include a pdf of your group’s Excel page.)
    Test Tube #
    
[Fe3+]initial=[Fe(SCN)2+]eq
    
A475
    
1
    
    0097
    
2
    
    0.149
    
3
    
    0.173
    
4
    
    0.248
    
5
    
    0.307
    
6
    
    0.460
    
7
    
    0.556
    Slope of line (A475 vs. [Fe(SCN)2+]) = ε =
    1
The slope represents the molar absorptivity coefficient.
Let's choose two points, say (0.097, A1) and (0.556, A7):
ε = (ΔA475) / (Δ[Fe(SCN)₂⁺])

ΔA475 = A7 - A1
Δ[Fe(SCN)₂⁺] = [Fe(SCN)₂⁺]₇ - [Fe(SCN)₂⁺]₁
Substitute the values:
ΔA475 = 0.556 - 0.097
= 0.459
Δ[Fe(SCN)₂⁺] = [Fe(SCN)₂⁺]₇ - [Fe(SCN)₂⁺]₁
= 0.556 - 0.097
= 0.459
Now, calculate the slope:
ε = ΔA475 / Δ[Fe(SCN)₂⁺]
= 0.459 / 0.459
= 1
So, the slope of the line (ε) for the Beer's Law plot is 1.
1. Abso
ance measurements to determine the Equili
ium Constant (20 pts)
    Test Tube #
    
[Fe(SCN)2+]eq...
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