One mole of sulfuryl chloride (SO2Cl2) decomposes to give one mole each of sulfur dioxide and...

Question

One mole of sulfuryl chloride (SO2Cl2) decomposes to give one mole each of sulfur dioxide and chlorine. A reaction mixture is with an initial concentration of sulfuryl chloride 2.0×10-2 M and at equilibrium is with a concentration of chlorine 1.1×10-2 M. Calculate the value of the equilibrium constant (Kc) of reaction.

Robert · Accepted Answer

The reaction is: 
SO2Cl2(g)⇌SO2(g)+Cl2(g) 
According to the reaction 1 mole of SO2Cl2(g) gives 1 mole of SO2(g) and 1 mole of Cl2(g). Hence   
equilibrium, [Cl2] should equal that of [SO2].   
Initial [SO2Cl2] = 2.0 × 10
−2 M 
At equilibrium, [Cl2] =  1.1×10
−2 M  
Therefore 
[SO2] = 1.

One mole of sulfuryl chloride (SO2Cl2) decomposes to give one mole each of sulfur dioxide and chlorine. A reaction mixture is with an initial concentration of sulfuryl chloride 2.0×10-2 M and at...

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