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You will need access to a calculator and a Periodic Table to answer this hour Marked Asmgarrtnt. Attempt Alt questions (a) State what the following terms tcptcsent and give an exampk of where net may...

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You will need access to a calculator and a Periodic Table to answer this hour Marked Asmgarrtnt. Attempt Alt questions (a) State what the following terms tcptcsent and give an exampk of where net may beat"1
wiw (Ii) w?v vtv (iv) mole fraction (v) mass fraction.
(b) What is the difference between the units 'Isnot and 'nor?
(c) (i) Name the due
(ii) How are they combated in a single equation? (MI) Use the ideal gts law% to calculate the mass of 25 ma of nature of 21% v/v oxygen (02) and 79% 'Maven (Na) which is at a temperature of 65'C and pressure of 2 tsar.
For net of the following compound,:
(i) aluminium chloride - AlC11 (Ii) iron (Ill) sulphate (fan sulPhatc) - ROO.), (iii) cobalt nitret -Co(N00,, (iv) sodium phasphate -Na,04 (v) ammo-butane -C4HuNH;
calculate. using values obtained from the Periodic Table given in lesson I:
(al the number of moles of that compound IntentIn a macs of 200
(b) the amount in grams per hue fg I 'I contained in a 2 M solution of the compound.
3. (a) Classify the following changes as either physical or chemical: (i) the melting of ice (ii) the permeation of sugar by cliwolving and re-oputallising (iii) the removal of an aced gas by dissemble; it in an alkali solution
(iv) the removal of water and gas from crude oil by sealing and then separating the oil by Oscillation into vareas fractions
(v) converting water into hydrogen and oxygen by electrolysis.
(b) Balance the folknivirg chemical equations. if necessary: (i) bloOso I. HO(Y) -y MaCl2No+ 11206, C12(2) (ii) 7a XXXXXXXXXXH230,(w -t Za XXXXXXXXXXH200, (iii) CtlisNligo • 02, -1, COuo • NA) 4. Nun (1+) Alto XXXXXXXXXX -• Al:01w + Zo, (v) Ca01s) + H200) -• Ca(OH)so,
(e) For each of the following balanced equations. cak-ulate the amounts &each reactant required to produce IOU kg of the product unclaimed (afore 10011 oonvalc.).
H2,21 +Six,. Hagen OU 3No0N0 H,004 -.N•9041.0 MPS
Answered Same Day Dec 20, 2021

Solution

Robert answered on Dec 20 2021
126 Votes
1)
a) i) W/W: weight percent by mass. This means weight percent of the solute in the total weight of
the solution. For example, 2% w/w indicates, 2 % of the solute present in the total weight of the
solution.
ii) w/V: Given amount of solute present in the total volume of the solution. 2% w/v indicates
that there are 2 g of substance present for every 100 mL of solution.
iii) v/v: quantinty indicated in terms of volume. The given volume of substance present in the
total volume of solution. For example, 2% v/v indicates, 2 mL of substance present for every 100
mL of solution
iv) mole fraction: The ratio between the number of mols of solute/solvent to total mols of
solution.

Number of molsof solute
Molefraction thesolute =
Total molsof soln

Mass fraction: The ration between the amount of solute to total mass of the solution is denoted
y mass fraction.

Massof solute
Mass fraction =
Total massof solution

) kmol = 1000 mol, so kmol is 100 times greater than mol.
c) i), ii) The three ideal gas laws and their mathematical representations are –
 
1
P Boyle's law
V

 P T Charle's law
 P n Avagadro's law
Therefore –
 
1
P n, ,T Avagadro's law
V

The ideal gas equation is -  
1
P R n T Avagadro's law
V
   
Thus -  PV nRT idealgasequation
iii) From the given data –
 
 
  
  
PV nRT idealgasequation
1atm
P = 2bar 2 ar 2.02
0.9862ba
100 ( ) 21 79
65 273 338
Therefore
2.02atm 0.1LPV
0.00727 mol
RT 0.0821L.atm/mol.K 338K
Therefore -
Average molecular weight = (32g
atm
V mL total volume mL mL
T K
n

 
  
 
  
  

  
 2 2O ) 0.21 +(28g N )(0.79) =...
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