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Will there be step by step help for each question? Document Preview: 1) You react (E)-2,7-dimethyl-4-octene with bromine, collect product, and then perform a second reaction with potassium hydroxide....

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Will there be step by step help for each question?
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1) You react (E)-2,7-dimethyl-4-octene with bromine, collect product, and then perform a second reaction with potassium hydroxide. a) Show the entire mechanism for these reactions. b) Given the following masses for starting material, intermediate, and final product (2.0g/4.26g/1.66g) calculate the percent yield for step 1, step 2, and the overall reaction. c) Given the following melting point data for the intermediate and product, briefly comment on purity. (intermediate: 166-170C, product: 145-155C) (2pts) 2) Acetone and propanal react via an aldol condensation in the presence of sodium hydroxide and then heat. Show the four possible products, and the mechanisms that lead to each one. 3) You wish to synthesize 1,1-diphenyl-1-propanol via Grignard technique. a) Show two possible synthetic pathways, along with their mechanisms. One of them should involve a ketone or aldehyde as a substrate, and the other should involve an ester substrate. Make a claim as to which is the more desirable synthetic pathway. b) Show what would happen if your Grignard reagent came into contact with water. For this reason, what precautions must be taken when performing a Grignard reaction? 4) What is the difference between an s-cis and s-trans diene? Which can undergo Diels-Alder cycloadditions and why?

Answered Same Day Dec 21, 2021

Solution

David answered on Dec 21 2021
133 Votes
Solution:TTs141212_67745_1
a) Step1: Formation of
omonium ion:
Bromonium ion
B
B
Step3: abstraction of  -hydrogen by OH - and eleimination of HBr :
OH
OH
- 2HB
KOH
Br+
Br2
Br -
H
2,7- Dimethyl-3,5-octeneH
Br+
Br -
B
B
a) Step1: Formation of
omonium ion:
Bromonium ion
B
B
Step3: abstraction of  -hydrogen by OH - and eleimination of HBr :
OH
OH
- 2HB
KOH
Br+
Br2
Br -
H
2,7- Dimethyl-3,5-octeneH
Br+
Br -
B
B

) Let us write down the reactants, intermediate and final products:
Mol.Wt. 140.27 g/mol 300.08 g/mol 138.25 g/mol
% yield = Mass of actual yield (in gm)
Mass of theoretical yield (in gm)
x 100
KOH
Br2
B
B
Mol.Wt. 140.27 g/mol 300.08 g/mol 138.25 g/mol
% yield = Mass of actual yield (in gm)
Mass of theoretical yield (in gm)
x 100
KOH
Br2
B
B

Theoretical yield in the 1st step = (300.08/140.27) x 2.00 gm = 4.28 gm
% - yield in the 1st step = (4.26/4.28) x100 = 99.53
Theoretical yield in the 2nd step = (138.25/300.08) X 4.26 gm = 1.96 gm
% - yield in the 2nd step = (1.66/1.96) x100 = 84.69
% yield of the overall reaction = (% - yield in the 1st step) x(% - yield in the 2nd step)
= (0.9953) x(0.8469) x100
= 84.29
2)
CH3
C
CH3
O
(i) Self condensation of acetone:
OH
H
OH
CH
CH3
CH=O
CH2
CH2
(iI) Self condensation of propanal:
CH3
OH
OH
C
C
C
CH3
CH3
CH3
O
CH2
O
CHCH3
CH3
C
CH3
O
(i) Self condensation of acetone:
OH
H
OH
CH
CH3
CH=O
CH2
CH2
(iI) Self condensation of...
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