The Vaporizarion of a liquid is 101 mmHg at 35.0oC. What is vapor pressure at 63.9oC, If delta Hvap...

Question

The Vaporizarion of a liquid is 101 mmHg at 35.0oC. What is vapor pressure at 63.9oC, If delta Hvap for the liquid is 39.3 KJ/mol?

Robert · Accepted Answer

Given:
Vapor pressure of a liquid is 101 mmHg at 35.0
o
C 
delta H of vaporization of liquid = 39.3 KJ/mole
We are asked to find out the Vaporization of a liquid is at 63.9 
o
C
the relationship between the vapor pressure of a liquid and temperature is 
described in the Clausius-Clayperon equation,
ln P =  - ∆Hvap * 1   +    C 
                R          T
where ln P is the natural logarithm of the vapor pressure, 
 ΔHvap is the heat of vaporization, 
 R is the universal gas constant (8.

The Vaporizarion of a liquid is 101 mmHg at 35.0oC. What is vapor pressure at 63.9oC, If delta Hvap for the liquid is 39.3 KJ/mol?

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