The specific rate constant of the decomposition of azoisopropane at 270°C ??is 2.06x10-7s -1....

Question

The specific rate constant of the decomposition of azoisopropane at 270°C ??is 2.06x10-7s -1. Calculate the percentage of the original sample decomposed after 25 s. And the time Necessary for 95% of the sample to decompose.

Robert · Accepted Answer

Time = (2.303/k)log(a/a-x) 
Since the reaction is a first 
order one. 
T is 25 sec and k = 2.068 10^-7 
Log(a/a-x)=22.36 * 10 ^-7 
a-x/a=0.99 
so 0.01 fraction of the 
reaction is complete 
Now for the second part we 
have a-x/a=20 
Since 95 % is decomposed so 
only 5% is left. 
T=(2.

The specific rate constant of the decomposition of azoisopropane at 270°C ??is 2.06x10-7s -1. Calculate the percentage of the original sample decomposed after 25 s. And the time Necessary for 95% of...

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