57203 Assignment 1) a. b. 2) a) b) 3) a) b) 11 gm ~5% Hence 100% ~ 20(11) = 220 gm 4) Molarity = no of moles in one litre of solution a) b) 35.6 gms of Magnesium Hydroxide equals = So no of moles present in 625 mL = Molarity = 5) a) Weight in gms of ammonium sulphate = 0.3(mol weight of amm,sulp) = 0.3(132.

Thanks in advance

1 answer below »

Thanks in advance

may-6-doc-1-2-2xvg2wd5.pdf

Answered Same Day May 08, 2021

Solution

Rajeswari answered on May 11 2021

139 Votes

57203 Assignment
1) a.
.
2) a)
)
3) a)
) 11 gm ~5% Hence 100% ~ 20(11) = 220 gm
4) Molarity = no of moles in one litre of solution
a)
) 35.6 gms of Magnesium Hydroxide equals =
So no of moles present in 625 mL =
Molarity =
5) a)
Weight in gms of ammonium sulphate = 0.3(mol weight of amm,sulp)
= 0.3(132.14) =...

SOLUTION.PDF

Thanks in advance

Solution

Answer To This Question Is Available To Download

Related Questions & Answers

Submit New Assignment