stoichemistry equation worksheet

Question

Rajeswari · Accepted Answer

1) 2Mg+O22MgO
24 gms of Magnesium reacts with 16 gms of Oxygen.
Hence 2 moles of Oxygen reacts with 4 moles of Mg with weight =96 gms.
2) For 15 moles of Oxygen moles of water produced = 6
For 4.85 moles of O2 water produced = 4.85*6/15 = 1.94 moles.
3) We find that 1 K gives 1 KCl by reaction.
i.e. 39 gms give 39+36 = 75 gm of KCl
2.5 gms of Potassium gives = 75*2.5/39 = 4.8076 gms.
No of moles = 4.8076/75 = 6.41x10-2
4) For 4 atoms of Fe no of moles produced = 2
Hence for 9.8x1024 atoms = 
5) 2NaClO3(s) = 2NaCl(s) + 3O2(g)
No of moles in 44.8 litre of Oxygen = 2
For 2 moles of Oxygen, moles of Nacl produced are = 2*2/3 = 4/3.
6) We have 1 moles of N2)5 gives 2 moles of Nitric acid
So 0.93 moles will give 2(0.93) moles with weight in gms
= 2(0.93)(63) =117.18gms
7) CaH2+2H2O  Ca()H)2+2H2
1 mole of CaH2 gives 2 moles of Hydrogen
So 9.2 moles will give 18.4 moles of Hydrogen = 18.4(22) litres
= 404.8 litres
8) We have as per equation 2 poles of lead nitrate give 4 moles of Nitrogen.
Hence 14.

stoichemistry equation worksheet

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