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Results of Experiment: (1) CaCl2(aq) + H2C2O4 *A white cloudy precipitate formed. Can't see through it. (2) CaCl2(aq) + K2C2O4(aq) *A thicker white precipitate than #1 formed. (3) Results of (1) + 6M...

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Results of Experiment: (1) CaCl2(aq) + H2C2O4 *A white cloudy precipitate formed. Can't see through it. (2) CaCl2(aq) + K2C2O4(aq) *A thicker white precipitate than #1 formed. (3) Results of (1) + 6M HCl *Nothing occurred . (4) Results of (3) + 6M NH3 *Precipitate thickened. (5) CaCl2(aq) + 6M NH3 *No precipitate ..........................[1] Ca2+ + C2O42- CaC2O4(s) +................[2] H3O + NH3 NH4+ + H2O ....^ [3] | ....\/...................[4] HC2O4- + H3O+ H2C2O4 + H2O + H2O (a) Account for the difference in behavior of H2C2O4 and K2C2O4 in tubes 1 and 2. Specifically, why does one solution form so much more CaC2O4(s)? (b) From this array of coupled equilibria, explain the effect of adding HCL on these equilibria. (Note that H3O+ praticipates in equilibria 2,3, and 4.) Why does the addition of HCl change the amount of CaC2O4(s)? (c) Consider the solutions 4 and 5, where NH3 was added. Does Ca(OH)2(s) form when NH3 is added to Ca(2+) solution (solution 5)? How does ammonia effect the amount of CaC2O4(s) present in solution 4? (d) Why does the H3O+ concentration have more influence on the precipitation of the salt of a weak acid, such as CaC2O4(s), than on the precipitation of the salt of a strong acid, such as AgCl(s) or CaSO4(s)?
Answered 84 days After Nov 20, 2021

Solution

Dr Shweta answered on Feb 12 2022
129 Votes
Solution
Results of Experiment:
(1) CaCl2(aq) + H2C2O4 *A white cloudy precipitate formed. Can't see through it.
(2) CaCl2(aq) + K2C2O4(aq) *A thicker white precipitate than #1 formed.
(3) Results of (1) + 6M HCl *Nothing occu
ed.
(4) Results of (3) + 6M NH3 *Precipitate thickened.
(5) CaCl2(aq) + 6M NH3 *No precipitate
(a) Account for the difference in behaviour of H2C2O4 and K2C2O4 in tubes 1 and 2. Specifically, why does one solution form so much more CaC2O4(s)?
(b) From this a
ay of coupled equili
ia, explain the effect of adding HCL on these equili
ia. (Note that H3O+ participates in equili
ia 2,3, and 4.) Why does the addition of HCl change the amount of CaC2O4(s)?
(c) Consider...
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