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Question 1= Consider the Electrochemical cell below which operates at 25oC. Zn(s)lZn2+( aq, 1.00 mol L-1)ll Au+(aq, 1.00 mol L-1) Au(s).What is the value of Ecell? What is the value of Ecell at...

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Question 1=

Consider the Electrochemical cell below which operates at 25oC.

Zn(s)lZn2+( aq, 1.00 mol L-1)ll Au+(aq, 1.00 mol L-1) Au(s).What is the value of Ecell? What is the value of Ecell at equilibrium?Also, what is the value of the cell potential, Ecell, after the cell has operated long enough at 25oC for (Zn2+) to have chnaged by 0.20 mol L-1?Does (Zn2+) increase or decrease by 0.20 mol L-1?

Question 2=

Waste water from a smelting plant contains both Lead and Silver ions.The concentrations are (Ag+)=0.020mol L-1 and (Pb2+)=0.15 mol L-1. Finely-divided, solid sodium chloride,NaCl, is added slowly to the waste water at 25oC. What is (Ag+) in the solution when PbCl2 just begins to precipitate?AgCl(s) and PbCl2(s), the Ksp values at 25oC are 1.8x10^-10 and 1.7x10^-5.

Question 3=

The equilibrium constant for the hypothetical reaction below is Kp=0.113 at 25oC.

A2(g) + B2(g) <---> 2AB(g)

An experiment is carried out at 25oC with an inital mixture in which P(A2)=1.0 atm and P(B2)=1.0 atm.What is the equilibrium partial pressure of AB(g)?

Also for the reaction below,

Kc=4.50x10^11 at 25oC.

A(g) +2B(g)<---> C(g)

In an experiment, 1.00 mol A and 1.00 mol B are combined in a 1.0 L reaction vessel.What are the equilibrium concentrations of A, B and C?

Answered Same Day Dec 21, 2021

Solution

Robert answered on Dec 21 2021
119 Votes
Question 1=
Question 1=
Consider the Electrochemical cell below which operates at 25oC.
Zn(s)lZn2+( aq, 1.00 mol L-1)ll Au+(aq, 1.00 mol L-1) Au(s).What is the value of Ecell? What is the value of Ecell at equili
ium?
Ans.
Zn(s) ( Zn+2 + 2e Eo = 0.76V
Au+ +e ( Au Eo = 1.83V
A. Eo cell = .76 + 1.83 = 2.59V
B. E cell at equili
ium = 0V
Also, what is the value of the cell potential, Ecell, after the cell has operated long enough at 25oC for (Zn2+) to have chnaged by 0.20 mol L-1?Does (Zn2+) increase or decrease by 0.20 mol L-1?
Overall reaction:
Zn (s) + 2Au+ ( Zn+2 + 2Au
Ecell = Eo cell – (0.0591/n) logQ
= 2.59 – (0.0591/2) log ([Zn+2]/Au+]^2)
=2.59 – (0.0591/2) log (1.2/0.6*0.6)
= 2.575V
[Zn+2] decrease by 0.2 mol/L
Question 2=
Waste water from a smelting plant contains both Lead and Silver ions.The concentrations are (Ag+)=0.020mol L-1 and (Pb2+)=0.15 mol L-1....
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