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Chem475_Fall12_HW4.1.nb Chem 475 Physical Chemistry I Fall 2009 HW 5 Due 10 AM Monday Dec. 14 1. Exhange Interaction A two-electron system in a 1-D Particle in a box occupying states | a > and | b> ,...

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Chem475_Fall12_HW4.1.n
Chem 475 Physical Chemistry I Fall 2009
HW 5 Due 10 AM Monday Dec. 14
1. Exhange Interaction
A two-electron system in a 1-D Particle in a box occupying states | a > and |
, is given by the wavefunction
Ψ Hx1, x2L =
1
2
8 a1 > b2 > - b1 > a2
where a1 > denotes electron 1 in state a >, etc. and the individual states a >, b > are normalized
a1 > ® Ψlabel=a Hx1L
a a > = 1; < b b > = 1, and < a b > = 0 Hunless a = bL
additional rules:
ai > bj > = bj > ai > Hcommutative propertyL
Ÿ Compute the expectation value of (x
`
1 - x
`
2L
2 for this two-electron wavefunction (expand the operator..). Here the
subscript of the operator denotes the coordinate space of the wavefunction that is appropriate. That is:
a2 < b1 x
`
2 a2
1 > = < b1 b1 > × < a2 x
`
2 a2 > = < a2 x
`
2 a2
o
a2 < b1 x
`
1 x
`
2 a1
2 > = < a2 x
`
2 b2 > × < b1 x
`
1 a1
Do this by first expanding the operator:
Ix`1 - x`2L2 ® x`12 + x`22 - 2 x`1 x`2
then consider each piece of the operator with the composite wavefunction like we did in class for H2+...
Ÿ Calculate < xab > for a > ® n = 1 particle - in - a - box state,
and b > ® n = 2 particle - in - a - box state.
Ÿ Compare your result with the expectation value of (x
`
1 - x
`
2L
2 for a two-particle wavefunction for
DISTINGUISHABLE particles i.e.
Ψ Hx1, x2L = a1 > b2
Chem475_Fall12_HW4.1.nb 1
2. Transition Dipole Moments
Compute the transition dipole moments (x, y, z components) for the following systems:
Ÿ A. n = 3 -> n = 4 electronic transition for the hexatriene molecule (linear particle in a box) for box length L
= 0.66 * 10.-9m
Ÿ B. L = 0 -> L = 1 (m=0) transition for a particle on a sphere
Ÿ C. L = 1 -> L = 2 (m=0) transition for a particle on a sphere
Ÿ D. 1s -> 2s transition for the hydrogen atom
Ÿ E. 1s -> 2p transition for the hydrogen atom
Chem475_Fall12_HW4.1.nb 2
Answered Same Day Dec 21, 2021

Solution

David answered on Dec 21 2021
125 Votes
Question 2: Find the Transition Dipole Moments in the following:
PAGE
1
Question 2: Find the Transition Dipole Moments in the following:
Solution: We are asked to compute the transition dipole moment,
m
.

Let us first find out what Transition Dipole Moment (TDM) means. Any electric dipole
moment observed between two transitions states i and f, is termed as TDM. Where i and f
are the Initial transition state and the final transition states respectively.
Now,
0
()..()
L
fifi
exxxdx
myy
=-
ò
where value of
m
varies from i to f.
Note that
0
fi
m
¹
for the transition to be valid.
Or,
0
2
sin..sin
L
f
i
fi
nx
nx
e
xdx
LLL
m
Õ
æö
Õ
æö
=-
ç÷
ç÷
èø
èø
ò
consider the generalized transition from i to f.
0
.coscos
L
fifi
fi
nnnn
e
xxx
LLL
m
æ-+ö
æöæö
=-Õ-Õ
ç÷
ç÷ç÷
ç÷
èøèø
èø
ò
.
On simplifying the integral over the limits,
22
211
fi
total
e
Lnn
m
æö
=--
ç÷
èø
V
On solving the denominator and further solving,
(
)
2
2
22
8
if
fi
fi
nn
eL
nn
m
æö
ç÷
=-
ç÷
Õ
-
èø

… (1)
Part A:
(
)
2
2
22
8
if
fi
fi
nn
eL
nn
m
æö
ç÷
=-
ç÷
Õ
-
èø
… (2)
(
)
2
2
22
83*4
32
fi
eL
m
æö
ç÷
=-
ç÷
Õ
-
èø
Given that, L= 0.66 x 10-9 m
e = 1.66 x 10-19 C
ni = 3
nf = 4
putting the values in equation (2) , we get:
(
)
19
9
2
2
22
8*0.66*10*1.66*103*4
32
fi
m
-
-
æö
ç÷
=-
ç÷
Õ
-
èø
Or,
30
2.09*10
fi
m
-
=
Part B: Mathematically,
12
*.
z
ezd
myyt
=
ò
where
z
m
is the electric field calculated
along the z-axis. We consider a hydrogen atom. In order to observe emission of radiation
from two states mz must be non-zero. That is
1212
*.
z
ezd
myyt
=
ò
(Using z = r cos
q
in spherical polar coordinates)
… (3)
We can consider each of the three integrals separately.
 
Any transition is not allowed when
12
z
m
comes out to be zero. We make the substitution
x = cos
q
, then, dx = -sin
q
d
q
 and the integral becomes
1
1
2
0
0
2
x
xdx
-=-
ò
Because, L1 = 0 and L2 = 1.
Or,
12
1
2
z
m
=-
coulomb-mete
The result is an even function evaluated over odd limits.
Here, a minus sign indicates that the...
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