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Please for our Mid-Term exam see our Week 6 Module. The midterm exam has 4 questions all problem solving. The format is that you have approximately one week to do the exam. Indeed take your time; you...

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Please for our Mid-Term exam see our Week 6 Module. The midterm exam has 4 questions all problem solving. The format is that you have approximately one week to do the exam. Indeed take your time; you have over one week in the comfort of your own relaxed environment to do the exam. You have one only one (1) attempt and I have given you 4 hours (you should be able to this in two hours or less) to do the exam. This MUST be done in one seating, and the best way is to do the exam is on a word document or had-written then scanned and posted as an attachment (word doc or pdf). The due date is Sunday May 14, 2023 LA time (PST) by Mid-Night (one minute after 11:59 pm on Sunday). You may choose any day of the week from now until the due date.
Answered Same Day May 14, 2023

Solution

Parvesh answered on May 15 2023
30 Votes
FINAL EXAM
1
Zijiefu Wang
Problem 1 (25 points): Independent random samples of 17 sophomores and 13 juniors
attending a large university yield the following data on grade point averages:
Sophomore Junior
3.04 2.56
1.71 2.77
3.3 2.7
2.88 3
2.11 2.98
2.6 3.47
2.92 3.26
3.6 3.2
2.28 3.19
2.82 2.65
3.03 3
3.13 3.39
2.86 2.58
3.49
3.11
2.13
3.27
At the 5% significance level, do the data provide sufficient evidence to conclude that the mean
GPAs of juniors is more than sophomores at this university?
a) What are the null and alternate hypotheses?
0 : j sH  
1 : j sH  
) What is the critical value?
df=17+13-2=28, 0.05 
tcrit= 1.7011 (Right tailed)
c) What is the Decision Rule?
Reject H0 if t> 1.7011
d) What is the test statistic?
2

sX
2( )s sX X jX
2( )j jX X
3.04 0.04 2.56 0.1764
1.71 1.2769 2.77 0.0441
3.3 0.2116 2.7 0.0784
2.88 0.0016 3 0.0004
2.11 0.5329 2.98 0
2.6 0.0576 3.47 0.2401
2.92 0.0064 3.26 0.0784
3.6 0.5776 3.2 0.0484
2.28 0.3136 3.19 0.0441
2.82 0.0004 2.65 0.1089
3.03 0.0361 3 0.0004
3.13 0.0841 3.39 0.1681
2.86 0.0004 2.58 0.16
3.49 0.4225 Total=38.75 Total=1.1477
3.11 0.0729
2.13 0.5041
3.27 0.1849
Total=48.28 Total=4.3236
48.28
2.84
17
38.75
2.98
13
s
s
s
j
j
j
X
X
n
X
X
n
  
  



2
2
( ) 4.3236
0.5198
1 17 1
( ) 1.1477
0.3093
1 13 1
s s
s
s
j j
j
j
X X
s
n
X X
s
n

  
 

  
 



2 2 2 2
2
( 1) ( 1) (17 1)(0.5198) (13 1)(0.3093)
0.1954
2 17 13 2
s s j j
p
s j
n s n s
s
n n
     
  
   
2
2.98 2.84
0.8596 ( four decimal places)
1 1 1 1
( ) 0.1954( )
17 13
j s
p
s j
X X
t
s
n n
 
  
 
t=0.8596
3
e) What is the decision?
Since, 0.8596< 1.701, do not reject the null hypothesis.
f) What does the decision infer?
The data do not provide sufficient evidence to conclude that the mean GPAs of juniors is not
more than sophomores at this university.
.................................................
4
Problem 2 (25 points ): The data below compares the prices of a single hot dog and a medium
soft drink at all the Major League Baseball stadia.
$ $
Hot
Dog
Soft
Drink
1 1
1.5 1.5
2.75 1.5
3 3
3.25 3.25
3.5 2.5...
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