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Only part one is required to be solved. Thanks

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Only part one is required to be solved.
Thanks
Answered Same Day Dec 23, 2021

Solution

Robert answered on Dec 23 2021
124 Votes
Process Diagram of the case considered in the question
T-S diagram of the process
a) Isentropic efficiency of tu
ine 1 = |Ha – Hb| / |Ha – Hb|S
= (3480 – 3069) / (3480-2958.5)
= 78.81
Isentropic efficiency of tu
ine 2 = |Hc – Hd| / |Hc – Hd|S
= (3462 – 3223) / (3462-3202)
= 91.9 %
Isentropic efficiency of tu
ine 3 = |Hd – He| / |Hd – He|S
= (3223 – 2414.56) / (3223-2317.6)
= 89.29 %
) Cyclic efficiency = Output from tu
ine / Input to (feed +boiler)
= (| Hb –...
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