Nitrogen gas adsorbed on a surface to the extent of 1.242 cm:' g-I at 350 kPa and 180 K, but at 240...

Question

Nitrogen gas adsorbed on a surface to the extent of 1.242 cm:' g-I at 350 kPa and 180 K, but at 240 K the same amount of adsorption was achieved only when the pressure was increased to 1.02 MPa. What is the enthalpy of adsorption of nitrogen on the surface?

Robert · Accepted Answer

the given data is as follows,
p
1
=350 kPa
T
1
=180 K
p
2
=1.02MPa= 1.02*1000 kPa= 1020 kPa
T
2
= 240 K
let the enthalpy of adsorption is
θ
H then from the formula,
ln = -
p
2 θ
H 1 1
p
1
 R T
2
 T
1
ln(1020/350) =
θ
Η/8.314(1/240−1/180)
θ
Η= ln(102/35)*8.

Nitrogen gas adsorbed on a surface to the extent of 1.242 cm:' g-I at 350 kPa and 180 K, but at 240 K the same amount of adsorption was achieved only when the pressure was increased to 1.02 MPa. What...

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