in a baeyer-villiger reaction, ketones (r2C=O) are converted to esters by using proxy acids. With an...

Question

in a baeyer-villiger reaction, ketones (r2C=O) are converted to esters by using proxy acids. With an unsymmetrical ketone, two possible esters can be formed, as shown for 3,3-dimethyl-2-butanone as starting material. How could you use spectroscopic techniques- H NMR, IR and MS to determine which ester is formed A or B? ester (A) ch3O-C=0-C(CH3)3 OR ester (B) ch3-C=O-OC(CH3)3

Robert · Accepted Answer

For the given reaction – 
O
3,3-dimethyl-2-butanone
Per acid
H3C O
O
 
 
We can distinguish the obtained product by using the different spectroscopic techniques as follows. 
 
 
 
IR:  
 
             11770cm observed for C=O  bonds nearer to –CH3 group.

in a baeyer-villiger reaction, ketones (r2C=O) are converted to esters by using proxy acids. With an unsymmetrical ketone, two possible esters can be formed, as shown for 3,3-dimethyl-2-butanone as...

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