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NEUTRAIISATION
OF 
5: ENTHALPY 
EXPERIMENT 
HAZARDS
POTENTIAL 
Safetyglassesmustbewornotalltimesinthelaborotory.T.0MsotutionsofNooH,HCl,and
CH3CooHareusedinthtisexperiment.Avoidcontoctwithyourskin,Washtheaffectedoreo
occurs'
if spilloge 
cold water 
with 
thoroughly 
INTRODUCTION
by carrying
be determined 
can 
in solution 
a chemical.reaction 
accompanying 
change 
The enthalpy 
the
between 
of energy 
transfer 
is.a 
process there 
ln this 
in a caloiimeter. 
reaction 
particular 
the 
out found by
be 
can then 
The enthalpy 
water' 
- usually 
liquid 
mass of 
a definite 
and 
substances 
reacting of
heat capacity 
the 
to determine 
need 
we also 
the tiquia. 
of 
iniemperature 
change 
the 
measuring 
reaction.
during the 
change 
the temperature 
it also undergoes 
since 
System, 
calorimeter 
the 
solution
heat of 
known 
using the 
is determined 
of a calorimeter 
capacity 
the heat 
ln this experiment, 
ofpotassiumnitrate.Theheatofneutralisationofsodiumhydroxidewithbothhydrochloricand
system'
calorimeter 
the same 
using 
is then determined 
acids 
acetic 
in a simple
pressure 
(atmospheric) 
a constant 
out at 
are carried 
experiment 
in this 
The reactions 
Vacuumflaskwhichisanexcellentthermalinsulator.Hencetheprocessiscarriedoutunder
(Tr)
lsothermal Process 
Products 
(Tr)
,
Reactants 
Adiabatic 
Process
(Calorimeter)
(Tr)
Reactants 
adiabatic(qo=AHo=0)ratherthanisothermal(Tconstant)conditions.Enthalpiesofreactionare
usuallytabulatedforisotl.rermalprocesses(e'g.at298K)butinthiscase,thereactantsandproducts
enthalpy
the 
between 
relationship 
the 
shows 
diagiam 
following 
The 
temperatures. 
at different 
are the
accompanying 
(AH.), and the one 
.utotir"t"t 
the aJabati. 
process in 
the 
accompanying 
change 
determine'
we wish to 
(AHr), which 
process 
isoth-ermal38
plus
process 
an isothermaI 
to 
equivalent 
process is thermodynamically 
the adiabatic 
We can see that 
Tr to Tz
from 
changed 
their temperature 
reactants have 
which the 
a...

David · Accepted Answer

HEAT OF NEUTRALISATION OF ACID AND BASE 
ABSTRACT:   
 Enthalpy of neutralisation is defined as the amount ot heat released 
when acid and base neuterlises to form 1 mole of water. For strong acid and weak 
acids, the values are different. This experiment is to find the heat of neutralisation of 
a strong acid with strong base and weak acid with a strong base. This method also 
helps us to study the concentration of the unknown acid is required. 
INTRODUCTION: 
Every chemical change is accompanied by a change in energy, usually in the 
form of heat. The energy change of a reaction that occurs at constant pressure is 
termed the heat of reaction or the enthalpy change. The symbol ΔH is used to 
denote the enthalpy change. This experiment is used to measure the heat of 
neutralization when an acid and base react to form 1 mole of water. 
This quantity of heat is measured experimentally by allowing the reaction to 
take place in a thermally insulated Styrofoam cup calorimeter. The heat liberated in 
the neutralization reaction will cause an increase in the temperature of the solution 
and of the calorimeter. The heat lost by the neutralization reaction will equal the heat 
gained by the water and calorimeter. 
Because we are concerned with the heat of the reaction and because some 
heat is absorbed by the calorimeter itself, in the first part of this lab, the heat capacity 
of the calorimeter is determined. This will be done by measuring the temperature 
change that occurs when a known amount of hot water is added to a known amount 
of cold water in the calorimeter. The heat lost by the water is equal to the heat 
gained by the cold water and the calorimeter. Once the heat capacity of the 
calorimeter is determined, we will then determine the heat released in the 
neutralization reaction.1 
METHOD 
The first step  in the lab was to find  the heat capacity constant of the 
calorimeter. For that 800 mL of water is taken in a calorimeter, stirred well and the 
temperature is noted at every 30 seconds for 5 minutes. To this solution,

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