I don't know if the bottom is correct should I use the density og ethanol to work it out or is mine...

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I don't know if the bottom is correct should I use the density og ethanol to work it out or is mine correct?
S2O32- is Sodium Thiosulphate
Cr2O72-is Dichromate
C2H5OH is Ethanol

6 mol of S2O32-is equivalent to 1 mol of Cr2O72-
2 mol of Cr2O72-is equivalent to 3 mol of C2H5OH 
1 mol of S2O32-is equivalent to 0.25 mol of C2H5OH

Concentration x volume / 1000

0.03 (given concentrationSodium Thiosulphate) of x 8.2 / 1000
=0.000246mol

Because: 1 mol of S2O32-is equivalent to 0.25 mol of C2H5OH

XXXXXXXXXX / 4 = 0.0000615mol

Because we diluted the wine 1:50 we

XXXXXXXXXXx 50 = XXXXXXXXXXmoles in 1 ml

We need to work out moles / dm3

XXXXXXXXXXmoles in 1 ml x 100 = XXXXXXXXXXmoles of ethanol in 100ml

We need to work out the ABV

Mr x mol = mass

46.08 (mass of alcohol) x XXXXXXXXXXdensity)

=14.167 %

David · Accepted Answer

Your calculations are correct, upto  calculation of number of mols of ethanol that should be present in 
the given sample of wine. But, I need to know, how much mL of wine was used up for determination. we 
got 0.0000615mol of  ethanol, in how much of mL of wine (is it 1 mL wine) , if we know that,

I don't know if the bottom is correct should I use the density og ethanol to work it out or is mine correct? S 2 O 3 2- is Sodium Thiosulphate Cr 2 O 7 2- is Dichromate C 2 H 5 OH is Ethanol 6 mol of...

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