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How would I go about solving the following problem? If 5.15 g Fe(No3)3 is dissolved in enough water to make exactly 150.0 mL of solution, what is the molarity of Fe(No3)3?

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How would I go about solving the following problem? If 5.15 g Fe(No3)3 is dissolved in enough water to make exactly 150.0 mL of solution, what is the molarity of Fe(No3)3?
Answered Same Day Dec 21, 2021

Solution

Robert answered on Dec 21 2021
132 Votes
How would I go about solving the following problem? If 5.15 g Fe(No3)3 is dissolved in enough water
to make exactly 150.0 mL of solution, what is the Molarity of Fe(No3)3?
Amount of Iron(III) nitrate = 5.15 g
Number of mols of Iron (III) nitrate = (5.15 g/241.86 g/mol) = 0.02129 mol
Thus –...
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