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How much Na2HPO4 must be added to NaH2PO4 to form a buffer with a pH of 7.45? Initially, 1 mole of NaH2PO4 is dissolved in 1 L of water. Ka of NaH2PO4 = 6.2x10-8

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How much Na2HPO4 must be added to NaH2PO4 to form a buffer with a pH of 7.45? Initially, 1 mole of NaH2PO4 is dissolved in 1 L of water. Ka of NaH2PO4 = 6.2x10-8
Answered Same Day Dec 26, 2021

Solution

David answered on Dec 26 2021
116 Votes
NaH2PO4 <===================> Na+ + H2PO4
-
...........................eq.1
H2PO4
-
===========> H
+
+ HPO4
-2
..................................................eq.2
the actual Ka of solution co
esponds to eq.2
Ka = [H+] [HPO4
-2
] / [H2PO4
-
]
According to...
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