Hi there,I appreciate if anyone can provide me answers for the attached questions. Please be sure to...

Question

Hi there,I appreciate if anyone can provide me answers for the attached questions. Please be sure to stick to the deadline.Kind regardsSima

Robert · Accepted Answer

SOLUTIONS: 
1. Option c 
2. Option a 
3. Option c 
4. Option a 
5. Option d 
6. Option d 
7. Option a 
8. Option b 
9. Option a 
10. Option b 
11. Option c 
12. Option b 
13. Option b 
14. Option c 
15. Option a 
16. Option d 
17. Option d 
18. Option b 
19. Option a 
20. Option b
SOLUTION 1: 
a) 
       2 24Cd s MnO aq Cd aq Mn aq
      
1
st
 half reaction: 
       24 28 5 4MnO aq H aq e Mn aq H O l
        
2
nd
 half reaction: 
   2 2Cd s Cd aq e    
Overall balanced equation: 
         2 24 25 2 16 5 2 8Cd s MnO aq H Cd aq Mn aq H O l
       
b) 
       2 2 2HgO s H O l e Hg l OH aq
      
52 10
365 365 24 60 60
I A
t days s
 
    
 
Atomic mass of Hg = 201 
Charge equivalent 52 10 365 24 60 60It         
Thus, 2 96500 201C Hg   
Calculated charge equivalent will be corresponding 
5201 2 10 365 24 60 60
0.66
2 96500
Hg
     


 
Mass of Hg produced will be 0.66g of Hg.
SOLUTION 2: 
a) 
(i) The final reaction is: 
       2 32 2 2 3Al s Cd aq Al aq Cd s     
Thus, 0 1.66 0.40 1.26cellE V    
(ii)    3 2Al s Al Cd Cd s 
b) 
 
 
 
0
2
3
3
2
2
3
6
30 303
ln
8.

Hi there, I appreciate if anyone can provide me answers for the attached questions. Please be sure to stick to the deadline. Kind regardsSima

Solution

Answer To This Question Is Available To Download

Related Questions & Answers

Submit New Assignment