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Find an expression for the root mean square deviation of the speed of molecules in a gas from its mean value, ?c = {c2 - c2}1/2.

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Find an expression for the root mean square deviation of the speed of
molecules in a gas from its mean value, ?c = {c2 - c2}1/2.
Answered Same Day Dec 23, 2021

Solution

Robert answered on Dec 23 2021
114 Votes
The root mean square deviation of the speed of the gaseous molecules from its
mean value is given by :-


Where X1 ,X2, ……………Xn are the average velocities of different particles
present in the gas .
So we can write Xrms = (X
2
average )
1/2
We know that , PV = nRT and also
...
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