TKT 4220
Concrete Structures 2
Department of Structural Engineering
1
EXERCISE 1
Equivalent load and load balancing
a) Determine the equivalent load from the prestressed reinforcement on the structures in
Figures 1, 2 and 3, and determine the co
esponding moment, axial and shear force
diagrams.
) The beam in Figure 1 has the following dimensions: w = 300 mm, h = 850 mm,
e = 350 mm and L = 8000 mm. The beam is subjected to an evenly distributed dead
load, g = 30 kN/m. What must the prestressing force F be in order to achieve exact
alance with the dead load?
c) The beam in Figure 1 is also subjected to an evenly distributed service load P. What is
the maximum value of this load without the beam cracking when the concrete’s tensile
strength is 3.0 N/mm2.
Figure 1: Simply supported beam
Figure 2: Simply supported beam with cantilevered end (parabolic profile between
supports, and straight profile at the cantilever)
Figure 3: Simply supported beam with cantilevered end (linear profile), for the
diagrams assume that F1 = F2 = F and e1 = e2 = e.
TKT 4220
Concrete Structures 2
Department of Structural Engineering
1
EXERCISE 1
Equivalent load and load balancing
a) Determine the equivalent load from the prestressed reinforcement on the structures in
Figures 1, 2 and 3, and determine the co
esponding moment, axial and shear force
diagrams.
) The beam in Figure 1 has the following dimensions: w = 300 mm, h = 850 mm,
e = 350 mm and L = 8000 mm. The beam is subjected to an evenly distributed dead
load, g = 30 kN/m. What must the prestressing force F be in order to achieve exact
alance with the dead load?
c) The beam in Figure 1 is also subjected to an evenly distributed service load P. What is
the maximum value of this load without the beam cracking when the concrete’s tensile
strength is 3.0 N/mm2.
Figure 1: Simply supported beam
Figure 2: Simply supported beam with cantilevered end (parabolic profile between
supports, and straight profile at the cantilever)
Figure 3: Simply supported beam with cantilevered end (linear profile), for the
diagrams assume that F1 = F2 = F and e1 = e2 = e.