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d) Explain how the haloform reaction can be used to distinguish between butan-2-one and propanal. Include a reaction mechanism for any reaction which occurs. If you have photographs of the iodoform...

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d) Explain how the haloform reaction can be used to distinguish between butan-2-one and propanal. Include a reaction mechanism for any reaction which occurs. If you have photographs of the iodoform experiment you may wish to include these.
d) Compounds having CH3CO- group or produces CH3CO- group after oxidation, responds to haloform reaction.
The propanal does not have a chloromethyl group whereas the ketone, butan-2-one has one chloromethyl group. So, The latter undergoes a haloform reaction whereas the former does not.
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Sharon Assignment Resubmission: Please correct the following? For one of the Esters below write a balanced equation and mechanism? Sample numberAcetic AcidFormic AcidBenzoic Acid2-hydroxy benzoic acid1EthanolNail varnish remover. Ethyl acetateVery effervescing. Thinners. Ethyl MethanoteGermoline smell. Ethyl benzoateNitrates. Ethyl hydroxyl benzoic acid2Propan-1-olFruity. Propyl AcetateNail polish remover PropylmethanateClover. Propyl benzanateFruity. Propyl hydroxyl benzoic acid.3Butan-1-olPear Drops. Bytyl acetateWeak pear drops. Butyl methanoatePineapple. Butyl benzoateButyl hydroxyl benzoic acid.4MethanolNail polish remover. Methyl acetateNo Smell. MethonoateDeep Heat.Methyl benzoateDeep heat. Methyl benzoate d) Explain how the haloform reaction can be used to distinguish between butan-2-one and propanal. Include a reaction mechanism for any reaction which occurs. If you have photographs of the iodoform experiment you may wish to include these. d) Compounds having CH3CO- group or produces CH3CO- group after oxidation, responds to haloform reaction. The propanal does not have a chloromethyl group whereas the ketone, butan-2-one has one chloromethyl group. So, The latter undergoes a haloform reaction whereas the former does not. A compound containing a chloromethyl group is treated with a halogen in alkaline solution – polyhalogenation of a-hydrogens takes place. A haloform along with a carboxylate anion are produced. Mechanism: Step1: Hydroxide ion abstract acidic proton from the ketomethyl group and produce an enolate. Step2: The enolate reacts with iodine to produce a halogenated ketone and iodide ion Step 3 & 4: Step 1 and step 2 are repeated to produce trihalogenated ketone: Step 5: Hydroxide ion attacks carbonyl carbon and free CI3- which is a good leaving group because of the stability imparted by three halogen atoms. You started with Iodine ???????????? You have mixed up using Iodine with chlorine in the...

Answered Same Day Dec 22, 2021

Solution

Robert answered on Dec 22 2021
141 Votes
1) Ester formation mechanism for ethanol and acetic acid:
HO
ethanol
O
HO
acetic acid
+
H
+
O
O
+ H2O
mechanism:
O
HO
acetic acid
H
+
O
HO
H
O
ethanol
H
O
O
HO
H
H
+
O
O
H2O
H
O
O
H2O +
-H
+
2) Iodoform mechanism:
CH3
O
OH
-
CH2
O
I...
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