Consider the hydrogenation of benzene to form cyclohexane C6H6(l) + 3H2(g)--C6H12(l)delta H for...

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Consider the hydrogenation of benzene to form cyclohexane C6H6(l) + 3H2(g)-->C6H12(l)

delta H for combustion to CO2(g) and/or H20(l) at 298 K for C6H12, C6H12 and H2 is -3270, -4000, and -286 kJ mol-1, respectively. Cp for C6H6, H2, and C6H12 is 100+0.3T, 20+0.05T and XXXXXXXXXXT J K-1mol-1

1)show that delta H for hydrogenation at 298 K is 128kJ mol-1

2)deduce delta U for hydrogenation at 298 K

3) deduce delta H for hydrogenation at 50 K

Robert · Accepted Answer

delta H, delta U, and combustion  
Consider the hydrogenation of benzene to form cyclohexane C6H6(l) + 3H2(g)--
>C6H12(l) 
delta H for combustion to CO2(g) and/or H20(l) at 298 K for C6H12, C6H12 and H2 is -
3270, -4000, and -286 kJ mol-1, respectively. Cp for C6H6, H2, and C6H12 is 
100+0.3T, 20+0.05T and 110+0.

Consider the hydrogenation of benzene to form cyclohexane C6H6(l) + 3H2(g)-->C6H12(l) delta H for combustion to CO2(g) and/or H20(l) at 298 K for C6H12, C6H12 and H2 is -3270, -4000, and -286 kJ...

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