Consider the following reaction: N2 + 3 H2 2 NH3. Initially, 4.25 moles of nitrogen gas and 6.33...

Question

Consider the following reaction: N2 + 3 H2  2 NH3. Initially, 4.25 moles of nitrogen gas and 6.33 moles of hydrogen gas are placed in a 3.35 L container. At equilibrium, 2.15 moles of NH3 was present. Calculate the number of moles of nitrogen and hydrogen at equilibrium.

Robert · Accepted Answer

Solution: 
N2 + 3H2 2 NH3 
From the above relation it is known that 1 mole of N2 and 3 moles of H2 combines to give 2 moles of 
NH3.  
Let us suppose that, if 1 mole of N2 and 3 moles of H2 present in the reaction vessel.

Consider the following reaction: N2 + 3 H2 2 NH3. Initially, 4.25 moles of nitrogen gas and 6.33 moles of hydrogen gas are placed in a 3.35 L container. At equilibrium, 2.15 moles of NH3 was present....

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