Calculate the magnetic moment of a) [Co(NH3)6]^+3 b) [CoF6]^+3

Question

Robert · Accepted Answer

(a) Electron arrangement in [Co(NH3)6]
+3
Formula for spin only magnetic moment µ = √n(n+2) 
N=number of unpaired electrons 
In this case, n=0 
Hence, magnetic moment, µ= 0,

Calculate the magnetic moment of a) [Co(NH3)6]^+3 b) [CoF6]^+3

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