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Calculate the absolute entropy of the following: a) 2.5 moles of Ar gas at p = 0.25 bar; b) 0.75 mole of O3 gas at p = 2.75 bar; c) 0.45 mole of a mixture of N2 (X=0.78) and O2 (X=0.22) at P(total) =...

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Calculate the absolute entropy of the following: a) 2.5 moles of Ar gas at p = 0.25 bar; b) 0.75 mole of O3 gas at p = 2.75 bar; c) 0.45 mole of a mixture of N2 (X=0.78) and O2 (X=0.22) at P(total) = 1.00 bar
Answered Same Day Dec 29, 2021

Solution

Robert answered on Dec 29 2021
111 Votes
moles of Ar , n = 2.5 mol
pressure, p = .25 ba
Answers:-
(a).
Then , the absolute entropy S is given as
S = nRln(p/po)
= 2.5*8.314*ln(.25)
= 2.5*8.314*(-1.39)
= - 28.89 JK-1mol-1
(b) . Moles of O
3
, n =0.75 mol
pressure, p = 2.75 ba
Then , the absolute entropy S is given as
S = nRln(p/po)
= 0.75*8.314*ln(2.75)
=0.75*8.314*1.012
...
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