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David · Accepted Answer

1) (a) Solution:
Given: 
Conductivity of the wall,               
Inner surface temperature,          
Outer surface temperature,          
Thickness of firebricks,                
So, heat transfer per unit time through the wall for unit area  
can be given by: 
 ̇  
 (  )
 
 
    (      )
   

Again, for         
Heat transfer per unit time,  ̇                    
Hence, 
Heat losses through the furnace wall per hour,
(b) Solution: 
Thermal conductivities as given are:
Firebricks,           
      
Insulating brick,           
      
Ordinary brick,           
       
Also,
Now, 
(i) Thermal resistance of each layer: 
Firebricks, 
   
  

Surface area is not mentioned. So, assuming surface area of furnace to be constant and equal to 1 
m
2
, thermal resistance of firebricks can be calculated as:
   
    
      
             
Similarly, 
Insulating brick, 
   
  
   
 
    
      
            
And, 
Ordinary brick, 
   
  
   
 
     
      

(ii) Heat loss per unit area 
The three layers of wall are in series so,

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