After the reaction, how much octane is left? Here is the balanced equation:...

Question

After the reaction, how much octane is left? Here is the balanced equation: 2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) number of moles of C8H18 reacted = 6.16×10−2 mol H2O produced = 0.554 mol oxygen is the limiting reactant

P · Accepted Answer

2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) 
number of moles of C8H18 reacted = 6.16×10−2 mol 
H2O produced = 0.554 mol 
oxygen is the limiting reactant
Solution:
 From the above equation,

After the reaction, how much octane is left? Here is the balanced equation: 2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) number of moles of C8H18 reacted = 6.16×10 −2 mol H2O produced = 0.554 mol oxygen is...

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