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(a) The vapour pressure of benzene between 10°C and 30°C fits the expression log( p /Torr) = 7.960 – 1780/( T /K). Calculate (a) the enthalpy of vaporization and (b) the normal boiling point of...

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 (a) The vapour pressure of benzene between 10°C and 30°C fits the expression log(p/Torr) = 7.960 – 1780/(T/K). Calculate (a) the enthalpy of vaporization and (b) the normal boiling point of benzene.

 (b) The vapour pressure of a liquid between 15°C and 35°C fits the expression log(p/Torr) = 8.750 − 1625/(T/K). Calculate (a) the enthalpy of vaporization and (b) the normal boiling point of the liquid.

Answered Same Day Dec 24, 2021

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Robert answered on Dec 24 2021
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