(a) The addition of 100 g of a compound to 750 g of CCl4 lowered the freezing point of the solvent...

Question

(a) The addition of 100 g of a compound to 750 g of CCl₄ lowered the freezing point of the solvent by 10.5 K. Calculate the molar mass of the compound.

(b) The addition of 5.00 g of a compound to 250 g of naphthalene lowered the freezing point of the solvent by 0.780 K. Calculate the molar mass of the compound.

David · Accepted Answer

a) We know: ΔTf = Kf *m 
Here, ΔTf = 10.5K, Kf = cryoscopic constant for CCl4 = 30K Kg/mol 
Thus, molality of solution =  
   
  

   

 
       
  
 
Molality = No of moles of solute / amount of solvent in kg 
Here solvent is CCl4 = 750g = 0.750kg 
Thus, moles of solute = 0.

(a) The addition of 100 g of a compound to 750 g of CCl 4 lowered the freezing point of the solvent by 10.5 K. Calculate the molar mass of the compound. (b) The addition of 5.00 g of a compound to 250...

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