A mixture of 50 g of hexane (0.59 mol C6H14) and 50 g of nitrobenzene (0.41 mol C6H5NO2) was...

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A mixture of 50 g of hexane (0.59 mol C6H14) and 50 g of nitrobenzene (0.41 mol C6H5NO2) was prepared at 290 K. What are the compositions of the phases, and in what proportions do they occur? To what temperature must the sample be heated in order to obtain a single phase?Method The compositions of phases in equilibrium are given by the points where the tie-line representing the temperature intersects the phase boundary. Their proportions are given by the lever rule (eqn 6.7). The temperature at which the components are completely miscible is found by following the isopleth upwards and noting the temperature at which it enters the one-phase region of the phasediagram.nαlα = nβlβ(6.7)

David · Accepted Answer

We denote hexane by H and nitrobenzene by N; refer to Fig. 6.20, which is a simplified 
version of Fig. 6.19. The point xN = 0.41, T = 290 K occurs in the two-phase region of the 
phase diagram. The horizontal tie line cuts the phase boundary at xN = 0.35 and xN = 0.83,

A mixture of 50 g of hexane (0.59 mol C 6 H 14 ) and 50 g of nitrobenzene (0.41 mol C 6 H 5 NO 2 ) was prepared at 290 K. What are the compositions of the phases, and in what proportions do they...

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