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a. In an experiment to measure the quantum efficiency of a photochemical reaction, the absorbing substance was exposed to 490 nm light from a 100 W source for 45 min. The intensity of the transmitted...

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a. In an experiment to measure the quantum efficiency of a photochemical reaction, the absorbing substance was exposed to 490 nm light from a 100 W source for 45 min. The intensity of the transmitted light was 40 per cent of the intensity of the incident light. As a result of irradiation, 0.344 mol of the absorbing substance decomposed. Determine the quantum efficiency.

b. In an experiment to measure the quantum efficiency of a photochemical reaction, the absorbing substance was exposed to 320 nm radiation from a 87.5 W source for 28.0 min. The intensity of the transmitted light was 0.257 that of the incident light. As a result of irradiation, 0.324 mol of the absorbing substance decomposed. Determine the quantum efficiency.

Answered Same Day Dec 24, 2021

Solution

Robert answered on Dec 24 2021
110 Votes
Answer:-
(a) 40% light was trasmitted so the absobed light = 100-40
= 60%
λ=490 nm = 490 x 10-9 m
now the energy of einstein associated with the radiation of wavelength 490 nm is given by
E = N
A
hc
λ
E= 6.022 x 1023 x 6.626 x 10-34 x 3 x 108
490 x 10-9
E = 6.022 x 6.626 x 3 x 106
490
E = 2.4 x 105 J
Intesity of light = 100 W = 100 Js -1
time = 45 min = 45 x 60 = 2700 s
so radiation energy abso
ed in 45 min with 60% absoption= 100 x 2700 x...
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