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A 61.08 g sample of Ba(OH)2 is dissolved in enough water to make 1.800 liters of solution. How many mL of this solution must be diluted with water in order to make 1.000 L of 0.100 M Ba(OH)2? im not...

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A 61.08 g sample of Ba(OH)2 is dissolved in enough water to make 1.800 liters of solution. How many mL of this solution must be diluted with water in order to make 1.000 L of 0.100 M Ba(OH)2?
 
im not sure what steps i need to do to solve this, i appreciate your help.
 
thank you so much :)
Answered 100 days After Jun 05, 2022

Solution

Baljit answered on Sep 14 2022
55 Votes
A 61.08 g sample of Ba(OH)2 is dissolved in enough water to make 1.800 liters of solution. How many mL of this solution must be diluted with water in order to make 1.000 L of 0.100 M Ba(OH)2?
Before Solving this problem lets first discuss the concept of Molarity
Molarity:- It is the number of moles of solute per 1 liter of solution.
Molarity(M)=Number of moles of solute (n) ÷ 1 liter of solution (V)
M= n/V
Now in our initial solution
given weight of...
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