A 26.79 g sample of a substance is initially at 23.6 C.
After absorbing 1001 J of heat, the...

Question

A 26.79 g sample of a substance is initially at 23.6 C.
After absorbing 1001 J of heat, the temperature of the substance is 198.1 C.
What is the specific heat (c) of the substance?I have the formula, I'm just not sure how to find Q.

Robert · Accepted Answer

A 26.79 g sample of a substance is initially at 23.6 C. After absorbing 1001 J of heat, the               
temperature of the substance is 198.1 C. What is the specific heat (c) of the substance? 
ANSWER 
 
Heat absorbed by a substance is given by; 
Q = mcΔT 
1001 = 26.79 x 10
-3
 * c * (198.

A 26.79 g sample of a substance is initially at 23.6 C. After absorbing 1001 J of heat, the temperature of the substance is 198.1 C. What is the specific heat (c) of the substance? I have the formula,...

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