4. The compound pars-dichlorobenzene, often used in mothballs, is composed of 49.02% carbon, 2.743%...

Question

4. The compound pars-dichlorobenzene, often used in mothballs, is composed of 49.02% carbon, 2.743% hydrogen, and 4824% chlorine by weight.
a. Deduce the empirical formula of para-dichlorobenzene. b. If the molecular weight of pars-dichlorobenzene is 147.0 g what is its molecular formula?
5. When heated together, lead(11) sulphide, PbS, and lead(11) oxide, PbO, produce elemental lead and sulphur dioxide, SO,. Write a balanced equation for this reaction. Calculate the number of moles of lead that can be produced from 14.0 g of
Calculate the number of grams of SO, that can be produced from 140 g of

005_3vgxzk-asap2cip.png 005_o1kxzk-quwuzjep.png 005_rvoxzk-wqyx312b.png

Robert · Accepted Answer

Solution.1 
 Step1: To calculate the empirical formula of the compound. 
Element Symbol % of 
element 
Atomic 
Mass 
Moles of the 
element=percentage/At.Mass 
Simplest 
molar ratio 
Simplest 
whole 
no. ratio 
Carbon C 49.02 12 49.02/12 = 4.085 4.085/1.36=3 3 
Hydrogen H 2.743 1 2.743/1 = 2.743 2.743/1.36=2 2 
Chlorine Cl 48.24 35.5 48.24/35.5 = 1.36 1.36/1.36=1 1
So, empirical formula is C3H2Cl. 
Step2. 
Empirical formula mass = 12x3 + 1x2 + 35.5 = 73.5g 
Given Molecular mass = 147 gmol-1 
Now, n = Molecular mass/ Empirical formula mass 
             = 147/73.5 = 2 
Molecular formula = n x Empirical formula  
                                  = 2 x C3H2Cl = C6H4Cl2 
Solution2.

4. The compound pars-dichlorobenzene, often used in mothballs, is composed of 49.02% carbon, 2.743% hydrogen, and 4824% chlorine by weight. a. Deduce the empirical formula of para-dichlorobenzene. b....

Solution

Answer To This Question Is Available To Download

Related Questions & Answers

Submit New Assignment