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3(O) Toluene (l) + CLSO 3 H + NH 3 3H-1, 3 Benzothiazde-2-thian + 3 H 2 O + HCl 7 x C (s) +2 x H(g)+ ½ Cl 2(g) + S (s) + 3O 2(g) + ½ N 2(s) Delta Hf Toluene 12 Kjmol Delta HfChlorosulphonic acid -597...

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3(O)
Toluene (l) + CLSO3H + NH3 3H-1, 3 Benzothiazde-2-thian + 3 H2O + HCl
7 x C(s) +2 x H(g)+ ½ Cl2(g) + S(s) + 3O2(g) + ½ N2(s)
Delta Hf Toluene 12 Kjmol
Delta HfChlorosulphonic acid -597 Kjmol
Delta Hf Ammonia XXXXXXXXXXKjmol
Delta Hf Water XXXXXXXXXXKjmol
Delta Hf3H-1,3 Benzothiazde-2-thian 205.5 Kjmol
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3(O) Toluene (l) + CLSO3H + NH XXXXXXXXXX3H-1, 3 Benzothiazde-2-thian + 3 H2O + HCl 7 x C(s) + 2 x H(g) + ½ Cl2(g) + S(s) + 3O2(g) + ½ N2(s) Delta Hf Toluene 12 Kj mol Delta Hf Chlorosulphonic acid -597 Kj mol Delta Hf Ammonia XXXXXXXXXXKj mol Delta Hf Water XXXXXXXXXXKj mol Delta Hf 3H-1, 3 Benzothiazde-2-thian 205.5 Kj mol

Answered Same Day Dec 23, 2021

Solution

David answered on Dec 23 2021
115 Votes
SolutionTTs160613_30633_30
∆Hf (reaction) = ∆Hf (products) - ∆Hf (reactants)
In the present case, ∆Hf (reaction) = ∑ [∆Hf(C7H5NS2) + 3X ∆Hf(H2O) + ∆Hf(HCl)]
- ∑ [∆Hf(C7H8)+ ∆Hf(ClSO3H)+ ∆Hf(NH3)]
Putting the values, ∆Hf...
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