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21.39$ The oxidation of HS03 by 02 in aqueous solution is a reaction of importance to the processes of acid rain formation and flue gas desulfurization. R.E. Connick et al. (Inorg. Chem. 34,...

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21.39$ The oxidation of HS03 by 02 in aqueous solution is a reaction of importance to the processes of acid rain formation and flue gas desulfurization. R.E. Connick et al. (Inorg. Chem. 34, XXXXXXXXXXreport that the reaction 2 HSO; XXXXXXXXXXSO4 + 2 H+ follows the rate law v = kr [HS0312 [H12. Given pH = 5.6 and an oxygen molar concentration of 2.4 x 10-4 mol dm-3 (both presumed constant), an initial HSO; molar concentration of 5 x 10-5 mol dm-3, and a rate constant of 3.6 x 106 dm9 mol-3 s-1, what is the initial rate of reaction? How long would it take for HSO; to reach half its initial concentration?
Answered Same Day Dec 22, 2021

Solution

Robert answered on Dec 22 2021
124 Votes
Answe
OR
2 2
6
5
6
2 2
6 5 2 6 2
16
13
[ 3 ] [ ]
3.6 10
[ 3 ] 5 10
[ ] ?
5.6
log[ ]
[ ] 2.5 10
[ 3 ] [ ]
3.6 10 [5 10 ] [2.5 10 ]
1237.5 10
1.237 10
ate kr HSO H
Kr x
HSO x
H
pH
pH H
H x
ate kr HSO H
ate x x x
ate x
ate x mol L
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
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  
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