15.00 ml sample of unknown aqueous snickel (ii) solution was treated and found to produce 0.0779g of...

Question

15.00 ml sample of unknown aqueous snickel (ii) solution was treated and found to produce 0.0779g of Ni(DMG)2 (molar mass 288.9155gémol)precipitate Assuming the density of the original Ni solution was 1.00g/ml , determine the percent Ni ( by mass) in the unknown solution.

Robert · Accepted Answer

Solution TTs 291012_51130_11 
Mol. Wt. of Ni(DMG)2 = 288.91 g 
0.0779g  Ni(DMG)2 = (0.0779 / 288.91) moles = 2.69×10
-4 moles  
The ionic equation for the precipitation reaction can be written as: 
                        Ni2+  +  2 DMG --- Ni(DMG)2 
One mole of Ni(DMG)2.

15.00 ml sample of unknown aqueous snickel (ii) solution was treated and found to produce 0.0779g of Ni(DMG)2 (molar mass 288.9155gémol)precipitate Assuming the density of the original Ni solution was...

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