1. The problem below concern CACL2.a XXXXXXXXXXgram of cacl2 is dissolved to 250 ml. What is the...

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1. The problem below concern CACL2.a XXXXXXXXXXgram of cacl2 is dissolved to 250 ml. What is the prepared molarity of the solutionb. what is the equilibrium molarity of chloride and the pcl value?c. A sample of cacl2 is dissolved in 250ml. A 5.00ml aliquot of the solution is dissolved to 250ml. Then a 5.00ml of the second solution is dissolved in 500ml. The final solution is analyzed and the chloride concentration is 3.60*10^-5 M. If all the chloride came from cacl2 how many grams cacl2 were added to the first solution?

Robert · Accepted Answer

Solution to TTs170912_38715_4
a. 0.135g CaCl2 = 0.135/ 111  Mole   [Mol Wt. of CaCl2= 111.0g]                    
      = 0.0012 Mole   
             250ml solution contains 0.0012 Mole  CaCl2 
           1000 ml ………………   0.0012   × 1000  Mole  CaCl2 
        250 
                                                  = 0.0048 Mole  CaCl2
              Molarity of the Solution = 0.0048 M.
b. Equilibrium  molarity is the molar concentration of a given 
species in a solution. 
             Since it is a dilute solution, CaCl2 can be considered to be   
             completely dissociated.
                     CaCl2  =  Ca
2+
 +  2 Cl
-

So, 0.

1. The problem below concern CACL2. a XXXXXXXXXXgram of cacl2 is dissolved to 250 ml. What is the prepared molarity of the solution b. what is the equilibrium molarity of chloride and the pcl value?...

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