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(1) Indicate whether each of the following molecule pairs are (a) identical, (b) enantiomers, or (c) diasteriomers. (a) (b) (c) (d) (e) (2) Draw the 3-dimensional representation for each of the...

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(1) Indicate whether each of the following molecule pairs are (a) identical, (b) enantiomers, or (c) diasteriomers. (a) (b) (c) (d) (e) (2) Draw the 3-dimensional representation for each of the following. (a) (2S,3R)-2-methoxy-3-chlorohexane (b) (R)-1,1,2-trimethylcyclohexane (3) Write the complete IUPAC name for the following compounds. (a) (b) (4) Designate True (T) or False (F) for each of the following statements. (a) A sample of an optically active substance that consists of a single enantiomer is said to have an enantiomeric excess of 100%. (b) The (R) enantiomer of a chiral compound always rotates the plane of polarized light to the right. (c) The meso form of a molecule can be either dextrorotatory or levorotatory. (d) 3-Methylcyclohexene is chiral. (e) trans-1,3-dichlorocyclohexane is chiral but the cis-isomer is not. (f) The difference in free energy between the reactants and the product is defined as the free energy of activation. (g) The first step in the SN1 reaction of tert-butyl chloride is the homolytic cleavage of the carbon-chlorine bond forming the tert-butyl carbocation and a chloride ion. (h) Carbon-hydrogen and carbon-carbon bonds located beta to a carbocationic center stabilize the cationic species by hyperconjugative electron delocalization. (i) The Hammond-Leffler postulate states that the structure of a transition state resembles the stable species that is nearest it in free energy. (j) Nucleophilicities are related to equilibria while basicities are related to rates of reaction. (k) Dimethylformamide and dimethylsulfoxide are polar protic solvents. 5. Complete each of the following reactions. Show the stereochemistry of the product when appropriate. (a) (b) (c) (d) (e) (f) (g) ( h ) (i) 6. Answer each of the following questions. (a) For each of the following circle which reaction will occur faster XXXXXXXXXXBromobutane or 1-Iodobutane with sodium azide in dimethyl sulfoxide XXXXXXXXXXBromo-2-methylbutane or 1-bromopentane with sodium iodide in acetone XXXXXXXXXXchlorohexane or cyclohexyl chloride with sodium azide in aqueous ethanol. (4)Solvolysis of 1-bromo-2,2-dimethylpropane or tert-butyl bromide in ethanol. (5)Solvolysis of isobutyl bromide or sec-butyl bromide in aqueous formic acid. (b) Give the mechanistic symbols (SN1, SN2, E1, E2) that are most consistent with each of the following statements. (1) Methyl tosylate reacts with potassium iodide in acetone only by this mechanism. (2) Ethyl bromide, 1-bromopropane, 1-bromobutane, and 1-bromopentane react with sodium ethoxide in ethanol mainly by this mechanism. (3) The substitution product obtained by acetolysis of tert-butyl bromide reacts mainly by this mechanism. (4) The elimination product obtained by methanolysis of tert-butyl bromide reacts mainly by this mechanism. (c) Arrange the following carbocations in the order of increasing stability. 7. A molecule has the molecular formula C6H10. Analyzing the following infrared spectrum and suggest a reasonable structure for this molecule. 8. Which of the following molecules is consistent with the accompanying infrared spectrum?
Answered Same Day Dec 22, 2021

Solution

Robert answered on Dec 22 2021
136 Votes
TTs030313_85085_1
Answers
Question #5
Sub division a)
The product is given below
Substitution from the side opposite to Br.
Sub division b)
Answer-
Pot tert butoxide (base)
elimination
ing flip to get antiperiplanarity of leaving groups
=

Sub division C) Answer
Pt, H2
cis addition
c
cis alkene is formed
Sub division d)
d)
Answer
N3- is a good nucleophile. So it undergoes nucleophilic substitution in the side chain.
The C that undergo is not steriogenic. Hence no special stereochemistry visible.
Sub division e) The reactions are given below
Sub division f) Answer
E2 elimination
Sub division g) Answer is given below
E1 elimination

Sub division h) Azide is a good nucleophile and OTs is a very good nucleophile. They
undergo SN2 reaction.
i) OH is a weak leaving group. So we convert it to a better leaving group bytrating
with MeSO2Cl in the first step. In the second step, the mesyl group is replaced by
azide(N3-) by SN2 process. As the C which undergo substitution is not
steriogenic, no obvious stereochemistry is involved in the SN2 ca
on.
Question # 6.
Question a)...
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