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Years = 30; MonthlyIncome = 50000/12; MonthlyAdjustment = 0.05/12; LoanStudent = 25000; LoanStudentInterest = 0.05/12; LoanStudentPayment = 300; LoanHigh = 1000; % ex: a credit...

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Years = 30;


MonthlyIncome = 50000/12;


MonthlyAdjustment = 0.05/12;


LoanStudent = 25000;


LoanStudentInterest = 0.05/12;


LoanStudentPayment = 300;








LoanHigh = 1000; % ex: a credit card


LoanHighInterest = 0.1/12;


LoanHighPayment = 200;








LoanLow = 0; %Use this to buy a car


LoanLowInterest = 0.04/12;


LoanLowPayment = 400;








MortgagePayment = 500 * ones(1, Years*12);


MonthlyExpenses = MonthlyIncome * 0.25;


Savings = 0;


SavingsInterest = 0.02;








NetIncome = 0;








for Index = 1: 1 : (Years*12)



%Anything left over from your income, goes towards your saving




%If negative apply to high loan








MonthlyIncome = MonthlyIncome * (1 + MonthlyAdjustment); % use a step function (ex: mod)








% Use the the table to determine the TaxRate based on annual income




% if ((MonthlyIncome * 12) <=>




% TaxRate = .15;




% elseif (((MonthlyIncome *12) > 50000) && ((MonthlyIncome *12) <=>




% TaxRate = .25




% else




% % ...




% end




NetIncome = MonthlyIncome * (1 - TaxRate);








%Student loan




if (LoanStudent > LoanStudentPayment)








else








end








% put some logic in here to only pay the mortgage if we still have




% anythng left on it...




% NetIncome = NetIncome - MortgagePayment;








%Low interest loan




if (Index == 1 || Index == 121 || Index == 241)




LoanLow = LoanLow + (MonthlyIncome * 12 * 0.5);




end




if (LoanLow > LoanLowPayment)








else








end








%High interest loan




if (NetIncome > LoanHigh)








else








end








%Plot savings and loans against the index



end




Answered 2 days After Dec 05, 2022

Solution

Baljit answered on Dec 07 2022
40 Votes
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