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Answered 3 days After Dec 09, 2023

Solution

Aakashgoyal answered on Dec 13 2023
18 Votes
solution
Q1. A particle at charge -4mC and mass 2 grams starts at point (1,1,1) with a velocity of 5ay m/s in a
magnetic field B=16ax W
m². Determine the position and velocity of the particle after 5 seconds.
Describe the motion of the charge.
Ans:
Given:
q= -4mC = -4x10-3 C
m= 2 gm = 2x10-3 kg
V= 5ay m/s
B= 16ax W
m2
We know that,
?

= ? ?

× ?
→( )
that is,
?

=− 4 × 10−3 ×5 ×16× ?
?
× ?
?( )
Therefore,
?

= ??

= 0. 32?
?
?
And,
?

=
0.32?
?
2 × 10−3
= 160?
?
?/?
Now distance d can be calculated as:
? = 12 ??
2 = 12 ×160×5
2 = 2000?
?
?
Since the particle was initially at (1,1,1) and is travelling in positive z-direction, therefore the position
after 5 seconds is (1,1,2001).
Q2. An infinitely long straight conductor ca
ies cu
ent I1
a) Find the force on each side of the triangular loop as
shown assuming...
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