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# every thing is attached

2 answer below Â»
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ANY NOT UN Ye GR FO NS Tes re Q
Answered 3 days After Dec 09, 2023

## Solution

Aakashgoyal answered on Dec 13 2023
solution
Q1. A particle at charge -4mC and mass 2 grams starts at point (1,1,1) with a velocity of 5ay m/s in a
magnetic field B=16ax W
mÂ². Determine the position and velocity of the particle after 5 seconds.
Describe the motion of the charge.
Ans:
Given:
q= -4mC = -4x10-3 C
m= 2 gm = 2x10-3 kg
V= 5ay m/s
B= 16ax W
m2
We know that,
?
â†’
= ? ?
â†’
Ã— ?
â†’( )
that is,
?
â†’
=âˆ’ 4 Ã— 10âˆ’3 Ã—5 Ã—16Ã— ?
?
Ã— ?
?( )
Therefore,
?
â†’
= ??
â†’
= 0. 32?
?
?
And,
?
â†’
=
0.32?
?
2 Ã— 10âˆ’3
= 160?
?
?/?
Now distance d can be calculated as:
? = 12 ??
2 = 12 Ã—160Ã—5
2 = 2000?
?
?
Since the particle was initially at (1,1,1) and is travelling in positive z-direction, therefore the position
after 5 seconds is (1,1,2001).
Q2. An infinitely long straight conductor ca
ies cu
ent I1
a) Find the force on each side of the triangular loop as
shown assuming...
SOLUTION.PDF