Problem 1The available bandwidth in a cluster is 1.25MHz. Find the number of channels per cellfor...

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Problem 1The available bandwidth in a cluster is 1.25MHz. Find the number of channels per cellfor the following systems:a.) AMPS: 30kHz/channel, 7cells/cluster;b.) NMTa: 25kHz/channel, 7cells/cluster;c.)NMTb: 12.5kHz/channel, 13cells/cluster;d.) GSM:25kHz/channel, 4cells/cluster;e.)CDMA: 1.25kHz/channel, 20channel/sector, 1 cells/cluster, 3 sectors/cell.Problem 2The delay spread in an environment TD is 5 micro seconds.The maximum Doppler spread FD is 200Hz.What is the appropriate range of the symbol duration of OFDM signals?Problem 3
	
Document Preview: Problem 1The available bandwidth in a cluster is 1.25MHz. Find the number of channels per cellfor the following systems:a.) AMPS: 30kHz/channel, 7cells/cluster; b.) NMTa: 25kHz/channel, 7cells/cluster; c.)NMTb: 12.5kHz/channel, 13cells/cluster; d.) GSM:25kHz/channel, 4cells/cluster;e.)CDMA: 1.25kHz/channel, 20channel/sector, 1 cells/cluster, 3 sectors/cell.Problem 2The delay spread in an environment TD is 5 micro seconds.The maximum Doppler spread FD is 200Hz.What is the appropriate range of the symbol duration of OFDM signals?Problem 3

David · Accepted Answer

Problem 1 
 
The available bandwidth in a cluster is 1.25MHz. Find the number of channels per cell 
for the following systems: 
 
a.) AMPS: 30kHz/channel, 7cells/cluster  
b.) NMTa: 25kHz/channel, 7cells/cluster  
c.) NMTb: 12.5kHz/channel, 13cells/cluster  
d.) GSM:25kHz/channel, 4cells/cluster 
e.) CDMA: 1.25kHz/channel, 20channel/sector, 1 cells/cluster, 3 sectors/cell. 
 
ANSWER: 
a.)  The Available Bandwidth in a cluster is 1.25 MHz.  
Advanced Mobile Phone System (AMPS) is an analog mobile phone system standard 
which has 30kHz/channel and 7cells/cluster. 
1.25 MHz is utilized for 30 KHz,  
Now the number of channels = 1.25 MHz / 30 KHz = 41.66 (we can say around 41 
channels are available) 
Now around 41 Channels, 41 Channels are utilized for 7 Cells which can re represented 
as   (6 – 1/7) 
Now we can say 6 cells are needed for 6 channels, 1 cell with 5 channels
b) The Available Bandwidth in a cluster is 1.25 MHz. which has 25 kHz/channel and 
7cells/cluster. 1.25 MHz is utilized for 25 KHz,  
 
Now the number of channels = 1.

Problem 1 The available bandwidth in a cluster is 1.25MHz. Find the number of channels per cell for the following systems: a.) AMPS: 30kHz/channel, 7cells/cluster; b.) NMTa: 25kHz/channel,...

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