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Please see the attached document. Thank you! Document Preview: CE 371 – Structural Analysis I Homework #2 due 7 September 2012, Friday, 8:30am A. Reading assignments: ? Start reading Chapter 4. B....

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CE 371 – Structural Analysis I Homework #2 due 7 September 2012, Friday, 8:30am A. Reading assignments: ? Start reading Chapter 4. B. Problem assignments: 7. The cantilever footing is used to support a wall near its edge A so that it causes a uniform soil pressure under the footing. Determine the uniform distribution loads, w and w , measured in lb/ft at pads A and A B B, necessary to support the wall forces of 8,000 lb and 20,000 lb. 8. Determine the reactions at supports A and B. The beam segments AC and CB are connected to each other with a “web only” splice at C. The splice at C can be considered as an internal pin. The beam AC sits freely, i.e. unconnected, on a support at A. As such, A can be taken as a roller support. Beam CB is attached to a column at B with channels both at the web (shear) and the flanges (flexural). Accordingly, the connection at B can be considered as a fixed support. 9. Determine the reactions at the supports A, C, and D. A is pin supported; C and D are roller supported. There is pin connection at B.10. The bulkhead AD is subjected to both water and soil-backfill pressures. Assuming AD is “pinned” to the ground at A, determine the required tension in the ground anchor BC necessary for equilibrium. Find the horizontal and vertical reactions at A. The bulkhead has a mass of 800 kg. For each planar structure given in problems 11 and 12: ? classify whether it is stable or unstable. Give a brief explanation of your reasoning. ? determine whether it is statically determinate or statically indeterminate. If it is statically indeterminate, what is the degree of statical indeterminacy. Explain your reasoning. Joints are illustrated as either friction-free pins (“pinned”) or non-yielding rigid joints (“rigid/fixed”). 11. continuous bent element b) XXXXXXXXXXa) cable c) d) 12.

Answered Same Day Dec 20, 2021

Solution

David answered on Dec 20 2021
135 Votes
7. At pad B, the load is applied centrally and hence the load distribution will be uniform. The system of
forces and structure should be taken as one, instead of treating it as two separate foootings. This will
ensure the equili
ium of the forces.
We have,
wA*2 + wB*3 = 20000 + 8000
 2wA + 3wB = 28000
Now, take moments about the extreme left edge.
wA*2*2/2 + + wB*3*(2+8+3/2) – 8000*(2+8+1.5) – 20000*(0.25) = 0
 2wA + 11.5wB = 97000
Solving, we get wA = 1823.53l
ft and wB = 8117.65l
ft
8. Consider the FBD of the segment AB as shown below.
FBD of AB
As can be seen, the segment is symmetrically loaded, hence,
RA = V = (4*6)/2 = 12kN
Now, refer to the FBD of segment BC. It acts as a cantilever beam with point loads as shown below.
FBD of BC
V+18 = RB
 RB = 30kN
Take moment about point B. So,
M + 18*2 +V*(2+2) = 0
 M= 84kN
9. First consider the segment BC. The FBD of BC is given below.
FBD of BC
Take moment about end C;
15*6 = V*(5+6)
 V = 90/11k
RC + V = 15
 RC = 75/11k (reaction at C)
Next consider the FBD of remaining segment shown below.
FBD of left segment
Take moment about end A;
V*(6+4) + 2*(6+4)2/2 = RD*8
 RD = 250/11k
Equating horizontal forces, we get;
HA = RD = 250/11k
Equating...
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