PLEASE ANSWER ONLY PROBLEM #2 OF KIRCHHOFF'S AND PROBLEM#2 OF MAXWELL. PLEASE SEND THE QUOTATION...

Question

PLEASE ANSWER ONLY PROBLEM #2 OF KIRCHHOFF'S AND PROBLEM#2 OF MAXWELL. PLEASE SEND THE QUOTATION ASAP.

David · Accepted Answer

1) Maxwell’s loop (or mesh) current method 
We can apply branch current method to this circuit, which would require 6 equations 1 6(for i i )  to be 
solved. 
Using mesh current method, we reduce 6 equations to 3 equations.
We take all the current in counter clock wise direction and we convert all the current source to voltage  
source  . 
  we have equations  for 3 mesh as : 
 
 
1 2 3 B 3 c 1 A
3 B 3 4 5 c 4 A
1 B 4 c 1 4 A
R R R I R I R I 0
R I R R R I R I 0
R I R I (R R )I 48
    
     
     
 
This can be written in the matrix form, AX C ,  
 
 
1 2 3 3 1 B
3 3 4 5 4 C
A1 4 1 4 6
R R R R R I 0
R R R R R I 0
I 48R R (R R R )
        
     
          
                
Here, voltage taken is – ve , because we are going from –ve terminal to +ve treminal
 
Hence , the solution for the above eq, is  
1X A C   
Now substituting the values of  R’s , we get ,

PLEASE ANSWER ONLY PROBLEM #2 OF KIRCHHOFF'S AND PROBLEM#2 OF MAXWELL. PLEASE SEND THE QUOTATION ASAP.

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