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Objectives This assessment...
Objectives This assessment item relates to the course learning outcomes 1, 3 and 4. It develops students' ability to design road geometric elements including roadside drainage. Details/Questions On...
1 answer below »
Objectives This assessment item relates to the course learning outcomes 1, 3 and 4. It develops students' ability to design road geometric elements including roadside drainage.
Details/Questions
On the contour plan shown in attached map, a two-lane two-way road is to be designed for 70km/hr speed joining Pub Road at Point A (CH0+000) and Fun Road at Point B alongside the pond . The design covers route location, horizontal and vertical alignments, cross-sectional elements, earthworks and road drainage design to achieve the most safety and economical outcome. The following are the requirements: • At Point A, the reduced level of the road is to be RL675. • At Point B, the reduced level of the mad is to be RL675. • There will be only one horizontal curve and only one vertical curve. • The truck traffic is negligible. Hence consider only cars for design. • Radius of horizontal curve [R= LN(student ID)x 8.4] is upward rounded to 5m. • Length of vertical curve [L= (student ID)14] is rounded to nearest 5m. • Side slope of cut is 1:1, fill is 1:2. Shrinkage factor = 10%. • Uniform ground slope at a particular chainage can be assumed. It can be obtained from contour map by joining two points at two sides of the road centreline, each at 20m distance perpendicular to the road centreline. • Lane width= 3.3m, sealed shoulder width= 1.2m. • Normal crossfall is -3% for lanes and -5% of sealed shoulder. • Rainfall intensity is 60mm/hr ( 1 year ARI) and 120mmihr (10 year ARI)
Within the constraints described above. design should include the following design elements(S: you cannot finalise these elements in sequence and iterative process is required): I. Sketch two alternative alignments. Choose one alignment for your design. Justify. (I mark) 2. Locate your alignment considering both vertical and horizontal controls. Coordinate both horizontal and vertical alignments. (I mark) 3. Design horizontal alignment (tangents and circular curve- also transition curves if required). Develop a horizontal alignment design table. (2 marks) 4. Design vertical alignment (grades and parabola) in detail. Develop vertical alignment design table. (2 marks)
5. Design superelevation for your road. (I mark) 6. Design side drain for your road for the runoff accumulated from road surfaces only. (2 marks) 7. Draw an appropriate longitudinal section showing both horizontal and vertical curves. (3 marks) 8. Determine and tabulate the cross section levels (kft end of the shoulder, left end of lane. centreline. right end of lane and right cnd of shoulder) at 20m interval. (2 marks) 9. Draw cross-sections at 40m interval including the side drain. (2 marks) 10. Calculate earthwork quantities using 40m cross-sections over the length of the road (pavement dcpth can be neglected). Draw mass-haul diagram and discuss the properties of your mass-haul diagram. ( 2 marks) 11. Check stopping sight distance on horizontal and vertical curves. (I mark) 12. Check road-ponding/aquaplaning safety (I mark)
005_spkb9jk-vkmxfqzj.pdf
Answered Same Day
Dec 20, 2021
Solution
David
answered on
Dec 20 2021
126
Votes
1. Two alternative alignments are drawn. The alignment shown by the solid line is
chosen because it has the property of
eaking monotony more than the other
one.
2. The alignment is located and coordinated in the following figure
Transition
Curve
Horizontal
Curve
Vertical
Curve
Gradients
3. Horizontal Alignment
Taking coefficient of longitudinal friction as 0.355 and coefficient of transverse
friction as 0.3. Speed given is 70km/hr that is 19.44 m/s. Now since the road has
to be designed for cars, taking the wheel base b of car as 2.44 m and height of
center of gravity h of the car to be approx. 1 m above the ground.
Thus, if the weight is W, then the centrifugal force to the weight ratio is
velocity2/(g*R) where g is 9.8 m/s2 and R is the radius of the horizontal curve.
Now, R = 165 m as per the instruction.
Considering that the vehicle mustn’t overturn when negotiating the curve gives
that
(2*h) > (v2/(gR)). Putting the values gives that this condition is satisfied.
Now, as per the exact formula for the angle of superelevation we have
Assuming that effective coefficient of transverse fiction is only 0.15 we have
angle of super elevation as tan θ = 0.0802 which give the angle of super
elevation θ to be approx. 5º.
Now, Safe Stopping Distance is v*t + v2 / (2*g*f) as there is no gradient during the
horizontal curve.
Here , assuming that the reaction time is 2.5 s and f=0.355=coefficient of
longitudinal friction, we have
S.S.D. = 102.8 m.
Now, assuming that the horizontal curve is 105.0 m long, we have the angle
equal to about 36º which is less hence OK.
Since this is a two lane two way road there is a total of n=4 lanes.
Taking the length of the vehicle (car) l to be 3.0m for simplicity.
Hence, Road widening is Wn = (n*l2)/(2*R) + v/(2.64*R0.5).
Here, the first part is due to mechanical widening and the second part is
psychological widening.
Putting down the values...
SOLUTION.PDF
SOLUTION.PDF
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Related Questions & Answers
Please complete assignment1 and project portfolio. Contents for project portfolio is in the assessment 2 file itself. thankyou.
Solved
Feb 01, 2025
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