MicroSticky Notechange the cooperators to (L) and solve the question again MicroSticky Notechange...

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MicroSticky Notechange the cooperators to (L) and solve the question again MicroSticky Notechange the capacitance to (L) and solve the question again   MicroSticky Notedo not do the first part of this question MicroTypewritten TextMicroTypewritten TextMicroTypewritten TextMicroTypewritten TextMicroSticky Notedo not do thos question MicroSticky Notedo not do this part of this question MicroSticky Notedo not do this part of this question

David · Accepted Answer

Solution 1: 
a) Definition are as follows: 
i) Accuracy: It is the closeness with which an instrument reading approaches the true 
value of the quantity being measured. 
ii) Precision: The term precise means clearly or sharply defined. Precision is the measure of 
degree of agreement to the value of the quantity measured. 
iii) Sensitivity: the degree of response of an instrument to the change in incoming signal is 
known as sensitivity. 
iv) Resolution: Resolution is the smallest change in the measured that the instrument can 
detect. 
v) Error: error is the difference between the true value and the measured value. 
b)     
i) Considering the figure from source end let resistance R1 and R2 be in series and 
then they have current I1. Similarly R3 and R4 are in series and have current I2. 
Hence the total current is:
KVL equation for source voltage is: 
    (     )  (     )]    
  
  (           )
(     )(     )

Applying current division rule 
   
     
           
   
   
     
           
   
KVL at output: 
      
     
           
      
     

   (   
     
           
    
     
           
)  
  (           )
(     )(     )
 
   (
  
     
 
  
(     )
)     
   (
   
            

(       )
)     
   (
   
      

 
)             
ii) When resistance is decreased by 0.005 
  
  (
   
                  

(       )
)     
    (
   
       

 
)              
Hence % error is: 
        
           
     
         
Hence error is of 50% 
iii) When R2 is also a gauge with temperature error then: 
  
  (
   
                        

(       )
)     
    (
   
   

 
)       
Hence % error is: 
        
       
     

Solution 2: 
a) Not done 
b) Current loops are ideal for data transmission as they are in sensitive to electrical noise. In this 
the minimum current is 4 mA and maximum is 20 mA. The signaling current flows through all the 
components even when the wire terminations are not perfect.

Micro Sticky Note change the cooperators to (L) and solve the question again Micro Sticky Note change the capacitance to (L) and solve the question again Micro Sticky Note do not do the first part of...

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