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Text: P.J. Antsaklis and A.N. Michel, Linear Systems. Birkhauser, Boston, 2006, 2nd . corrected printing (ISBN XXXXXXXXXX Problem-1 Problem-2 Problem-3 Problem-4 Problem-5

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Text: P.J. Antsaklis and A.N. Michel, Linear Systems. Birkhauser, Boston, 2006, 2nd . co
ected printing (ISBN XXXXXXXXXX
Problem-1
Problem-2
Problem-3
Problem-4
Problem-5
Answered Same Day Dec 21, 2021

Solution

Robert answered on Dec 21 2021
126 Votes
Solution 1:
[



]
[



] [



]
[



]
[



]
Hence generalizing:
[
( )


]
Hence A^100 is:
[
( )


]
[



]
Solving second part
[( ) ]
[



] [



]
[



]
| | ( )( ( ))
[ ]

( ( ) )
[
( ) ( )
( ) ( )
( )
]
[ ]
[






( )

( )

( )


]





[( ) ] [



]
Hence
[



]
Solution 2:
a) [


]
[ ] [


] [


]
[ ] [

( )
]
| | ( ( ( ))
| | ( )
[ ]

( )( )
[


]
[ ]
[




( )( )

( )( )

( )( )

( )( )]


[ ]
[






[

( )

]


[

( )

]


[

( )

]


[

( )

]
]


[ ] [

( )


( )


( )


( )
]
[ ] [



( )


( )


( )


( )
]
[



( )


( )


( )


( )
]
) Converting to state space:
Taking state variables as:
̇
̈ ̇ ̇
This fails the state space. Hence we modify our state variables
̇
̇
̇
̇ ̈ ̇
̈ ̇ ̇
Substituting ̇
̈ ̇ ( )
̈ ̇
Hence representing in state space
[
̇
̇
] [


] [


] [


]
Now taking laplace of state space equation to find x(t)
( ) ( ) ( ) ( )
Where A and B are as shown:
[


]
[


]
And x(0) is initial condition:
[
( )
( )
] [


]
( ) ( ) ( ) ( ) ( )
[


] [


]
[


]
| | ( ( ) )
| | ( )
( )

( )
[


]
( )



Putting values in...
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